find the equation of the circle which touches the x axis and center is (3,4)
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The general equation of a circle is
(x-h)^2 + (y-k)^2 =r^2
Since the line lies on x axis, y=0
h=3 k=4
So the equation is
(x-3)^2 +(4)^2 =r^2
x^2+9-6x +16 =r^2
x^2-6x+25 =r^2
HOPE IT HELPS YOU... ☺☺☺
(x-h)^2 + (y-k)^2 =r^2
Since the line lies on x axis, y=0
h=3 k=4
So the equation is
(x-3)^2 +(4)^2 =r^2
x^2+9-6x +16 =r^2
x^2-6x+25 =r^2
HOPE IT HELPS YOU... ☺☺☺
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