Question

Find the equation of the circle which touches x - axis at a distance +3 from origin and cuts an section at y- axis of length 6 units.​

Answer 1

Answer:

Center (,), radius squared , circle equation

(−)2+(−)2=

Interpreting the question, we’re told (3,0) is on the circle, and the axis is tangent to the circle at that point. We can skip the calculus and note the radius through that point is perpendicular to the axis, so we must have =3, i.e. the center is (3,). We’re also told (0,6)is on the circle.

Let’s substitute both points, (3,0) first.

(3−3)2+(0−)2=

=2

(0,6) next.

(0−3)2+(6−)2=2

45−12=0

=15/4(−3)2+(−15/4)2=(15/4)2

Circle equation:

(−3)2+(−15/4)2=(15/4)2

Answer 2

Step-by-step explanation:

RIP

SUSHANT SINGH RAJPUT

GONE TOO SOON...