Question

Find the equation of the circle whose center is (a,b) which passes through orgin

Answer 1

centre (a,b) point (0,0)
so h = a & k = b
now by distance formula we will find radius
r^2 = (0-a)^2 + (0-b)^2
r^2 =a^2 + b^2
putting value of all this in equation of circle i.e.
(x-h)^2 +(y-k)^2 = r^2
(x-a)^2 +(y-b)^2 = a^2 + b^2
x^2 + a^2 - 2xa +y^2 + b^2 -2yb =a^2 + b^2
x^2 - 2xa + b^2 -2yb = 0
x^2 + b^2 -2xa - 2yb =0