Find the equation of the circle whose centre is (1,-3) and which touches the line 2x-4y-4=0.
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4 y=2 x-4
y=2/4 x-4/4
y=1/2 x-1
slope=1/2
equation
y-ý1=m (x-x1)
y+3=1/2 (x-1)
2(y+3)=1(x-1)
2y+6=x-1
x-2y-1-6=0
x-2y-7=0
y=2/4 x-4/4
y=1/2 x-1
slope=1/2
equation
y-ý1=m (x-x1)
y+3=1/2 (x-1)
2(y+3)=1(x-1)
2y+6=x-1
x-2y-1-6=0
x-2y-7=0
amancr72013:
Your answer is wrong
sorry
what is the answer??
(x-1)^2+(y+3)^2=1/5
leave this question , actually I have solved it
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