Question

Find the equation of the circle whose centre is (2-3)and radius is 8

Answer 1

Answer:

Step-by-step explanation:

Answer 2

The equation of the circle whose centre is (2, - 3) and radius is 8 is x² + y² - 4x + 6y - 51 = 0

Given :

The circle has centre (2, - 3) and radius is 8

To find :

The equation of the circle

Concept :

The equation of a circle with centre (h, k) and radius r is given by

(x – h)² + (y – k)² = r²

Solution :

Step 1 of 2 :

Write down centre and radius

Here it is given that circle has centre (2, - 3) and radius is 8

Comparing with centre (h, k) and radius r we get

h = 2 , k = - 3 , r = 8

Step 2 of 2 :

Find the equation of the circle

The required equation of the circle is

$\displaystyle \sf{ {(x - 2)}^{2} + {(y + 3)}^{2} = {8}^{2} }$

$\displaystyle \sf{ \implies {x}^{2} - 4x + 4 + {y}^{2} + 6y + 9 = 64 }$

$\displaystyle \sf{ \implies {x}^{2} + {y}^{2} - 4x + 6y - 51 = 0 }$

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