Question

Find the equation of the circle whose centre is (3, -2) and which cuts off an intercept of length 6 on the line 4x - 3y + 2 =0

Answer 1

Step-by-step explanation:

length of perpendicular from. centre. to line ==

(4×3 + 3×2 + 2)/(4^2 + 3^2)^1/2 = 4

radius of circle = (4^2 + 3^2)^1/2 == 5

equation of the circle = (x - 3)^2 +(y+2)^2 = 25