Question

: Find the equation of the circle whose centre is (3, 4) and which touches the line 5x+12y=1.

Answer 1

Answer:

( x-3)² + ( y-4)² = (62/13)²

Step-by-step explanation:

radius R = (5×3 + 12×4 -1) ÷ 13 = 62/13

equation :

( x-3)² + ( y-4)² = (62/13)²