Question

Find the equation of the circle whose centre is (-4, 5) and circumference is 8π units.​

Answer 1

Answer:

equation of circle = (x - h)^2 + (y - k)^2 = r2

=(x-(-4) )^2+ (y-5)^2=r^2

( x +4)^2 + ( y-5)^2. = r^ 2

x^2 + 4^2+2×x×4 + y^2 + 5^2-2×y×5 = ( 8π)^2

x^2+16+8x + y^2 +25-10y = 16π^2

x^2+ y^2 +8x -10y +41-16π^2=0