Question

Find the equation of the circle, whose end points of a diameter are A(1, 5) and B(-1, 3)

Answer 1

Answer:

given: A(1,5) and B(-1,3)

Step-by-step explanation:

• let center of circle be P and its co-ordinates is P(x,y) . now, PA square=PB square .so (x-1) square+(y-5) square=(x+1) square +(y-3) square
• x square+1 -2x + y square+25-16y = x square +1 +2x +y square+ 9 - 6y . 26-2x-16y=2x-6y+10
• -4x-16y-16y+26-10=0
• -4x-32y+16=0
• -4(x+8y-4)=0
• x+8y-4=0.