Question

find the equation of the circle with center c and radius 'r' where C= (2,-3), r=4

Answer 1

Answer:

(x-2)^2+(y+3)^2=16

Step-by-step explanation:

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Answer 2

Answer:

(x-2) square + (y+3) square= (4) square

or, (x square-2×x×2+ (2) square) + (y square +2×y×3+(3) square= 16

or, x square + y square - 4x + 6y + 4 + 9 = 16

Ans: x square + y square - 4x + 6y - 3 = 0