Question

Find the equation of the circle with center c and radius r where C =(-7, -3), r = 4​

Answer 1

Answer:

Yo whats up. is it correct?

Explanation:

Answer is in the pic

Answer 2

Answer:

The equation of the circle is $x^{2} + y^{2} + 14x +6y + 42 = 0$

Explanation:

Given: Centre c =(-7,-3)

radius r = 4

To find: The equation of the circle

Formula used: $(x+h)^{2} + (y-k)^{2} = r^{2}$

Solution:

Centre c is (-7 , 3)

Radius r = 4

Equation of the circle is

$(x+h)^{2} + (y-k)^{2} = r^{2}$

$(x+7)^{2} +(y+3)^{2} = (4)^{2}$

$x^{2} +49 + 14x + y^{2} +9 +6y = 16$

$x^{2} + y^{2} + 14x + 6y + 58 - 16$

$x^{2} + y^{2} + 14x +6y + 42 = 0$

Final answer :

The equation of the circle is $x^{2} + y^{2} + 14x +6y + 42 = 0$

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