Question

Find the equation of the circle with centre (0.-2) and radius
2
A. 02 + y2 + dy=0
C. 1? + y² + 2y = 0
B. 121 - Lục )
D. r?+ y + 4y = 0​

Answer 1

Answer:

Option D

Step-by-step explanation:

the general equation of a circle with its centre (h,k) and radius r is given by

(x-a)²+(y-b)²=r²

given, the centre is (0,-2) and the radius is 2

Therefore

${(x - 0)}^{2} + {(y - ( - 2))}^{2} = {2}^{2}$

on simplifying we get,

${x }^{2} + {(y + 2)}^{2} = 4$

${x }^{2} + {y}^{2} + 4y + 4 = 4$

This is the final equation of circle.

${x }^{2} + {y}^{2} + 4y = 0$

Therefore, option d

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