Find the equation of the circle with centre (1, 1) and radius 2^0.5
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Given : circle with centre (1, 1) and radius 2^0.5
To find : Equation of circle
Solution:
Equation of circle
(x - h)² + ( y - k)² = r²
(h , k ) is center of circle
r = radius of circle
Center is ( 1 , 1) => h = 1 & k = 1
radius of circle = √2 => r = √2
putting these values
(x - 1)² + ( y - 1)² = (√2)²
=> x² - 2x + 1 + y² - 2y + 1 = 2
=> x² + y² - 2x - 2y = 0
x² + y² - 2x - 2y = 0 is the equation of the circle with centre (1, 1) and radius 2^0.5
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