Question

find the equation of the circle with centre (-2,3) and radius root 5....plz answer it
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Answer 1

Answer:

equation of the circle with centre (-2,3)and radius √5 is

(x+2)^2+(y-3)^2=(√5)^2

=> x^2+4x+4+y^2-6y+9=5

=> x^2+y^2+4x-6y+4+9-5=0

=> x^2+y^2+4x-6y+8=0