Question

Find the equation of the circle with centre at (2,-3) and having radius 5​

Answer 1

Answer:

Here, centre (h, k) = (2, - 3) and radius r = 5 units. Hence, the equation of a circle with centre at (2, - 3) and radius 5 units is x 2 + y 2 − 4 x + 6 y − 12 = 0 .

Step-by-step explanation:

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Answer 2

Answer:

The equation of circle with centre at (h, k) and radius 'r' is

(x - h)2 + (y - k)2 = r2

Calculation:

We know that, the equation of circle with centre at (h, k) and radius 'r' is

(x - h)2 + (y - k)2 = r2

Here, centre (h, k) = (2, - 3) and radius r = 5 units.

Hence, the equation of a circle with centre at (2, - 3) and radius 5 units is

(x - 2)2 + (y + 3)2 = 52

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Hence, the equation of a circle with centre at (2, - 3) and radius 5 units is .