Find the equation of the circle with Centre at (, −)and which passes through
the point (, −).
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Answer:
The centre of the given circle is (h,k) = (2,2).
Since, the circle passes through the point (4,5), the radius r of the circle is the distance between the points (2,2) and (4,5).
Therefore,
r=
(−2)
2
+(−3)
2
=
4+9
=
13
Thus, the equation of the circle is :
(x−h)
2
+(y−k)
2
=r
2
(x−2)
2
+(y−2)
2
=13
x
2
+y
2
−4x−4y−5=0
Step-by-step explanation:
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