Question

Find the equation of the circle with Centre at ( , − )and which passes through

the point (, − ).​

Answer 1

Answer:

The centre of the circle is given as (h,k)=(2,2)

Since the circle passes through point (4,5), the radius (r) of the circle is the distance between the point (2,2) and (4,5).

r=

(2−4)

2

+(2−5)

2

=

13

Thus, the equation of the circle is

(x−h)

2

+(y−k)

2

=r

2

(x−2)

2

+(y−2)

2

=13

x

2

−4x+4+y

2

−4y+4=13

x

2

+y

2

−4x−4y−5=0

Step-by-step explanation:

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