Math, asked by rohit3785, 1 year ago

find the equation of the circle with centre (h,k)and touching (1) x-axis (2)y-axis

Answers

Answered by Anonymous
24
Hi Mate!!

1). Equation of circle touching x - axis is

( x - h )² + ( y - k )² = k²

2) Equation of circle touching y -axis is

( x - h )² + ( y - k )² = h²

rohit3785: how the eq is made
rohit3785: please give detail
Anonymous: standard equation of circle is ( x - h )² + ( y - k )² = R² where h,k are co-ordinates of circle and R is radius ......here in ist case R = k and in second case R = h
Answered by harendrachoubay
8

1) x-axis, (x-h)^{2} +y^{2} =a^{2}

2) y-axis,x^{2} +(y-k)^{2} =a^{2}

Step-by-step explanation:

To find, the equation of the circle with centre (h, k)and touching 1) x-axis

2) y-axis

We know that,

The equation of a circle with centre at (h, k) and radius equal to a

= (x-h)^{2} +(y-k)^{2} =a^{2}

1) x-axis

Puy k = 0, we get

The equation of the circle with centre (h, k)and touching x-axis

(x-h)^{2} +(y-0)^{2} =a^{2}

(x-h)^{2} +y^{2} =a^{2}

2) y-axis

Puy h = 0, we get

The equation of the circle with centre (h, k)and touching y-axis

(x-0)^{2} +(y-k)^{2} =a^{2}

x^{2} +(y-k)^{2} =a^{2}

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