Question

find the equation of the circle with centre of the radius r where c(-7,-3)​

Answer 1

Answer:

x^2+y^2+14x+6y+42=0

Step-by-step explanation:

centre= (-7,-3)

radius=4

(x-(-7))^2 + (y-3)^2 = y^2

(x+7)^2 + (y+3)^2 = y^2

x^2+49+14x+y^2+9+6y=16

X^2+ y^2+14x+6y+58-16=0

x^2+y^2+14x+6y+42=0

here you go

hope it helps