Question

find the equation of the circle with the centre 1 by 2 and 1 by 4 and radius 1 by 12


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Answer 1

Answer:

(x-1/2)^2 + (y-1/4)^2 = (1/12)^2

Answer 2

Answer:-

★ Given:-

Centre (1/2, 1/4) and radius 1/12

Let us consider the equation of a circle with centre (h, k) and

Radius r is given as (x – h)² + (y – k)² = r²

So, centre (h, k) = (1/2, 1/4) and radius (r) = 1/12

The equation of the circle is

(x – 1/2)² + (y – 1/4)² = (1/12)²

x² – x + ¼ + y² – y/2 + 1/16 = 1/144

x² – x + ¼ + y² – y/2 + 1/16 = 1/144

144x² – 144x + 36 + 144y² – 72y + 9 – 1 = 0

144x² – 144x + 144y² – 72y + 44 = 0

36x² + 36x + 36y² – 18y + 11 = 0

36x² + 36y² – 36x – 18y + 11= 0

Therefore, the equation of the circle is 36x² + 36y² – 36x – 18y + 11 = 0