Question

Find the equation of the circle x2 + y2 + 8x -16y + 64 = 0 in the mirror line x =0​

Answer 1

Answer:

$(x+4)^{2}+(y-8)^{2}$=16

Step-by-step explanation:

(x-(-4))^2+(y+8)^2=16

(x-4)^2(y+8)^2=16

radius =4

Answer 2

Answer:

$x {}^{2} + y {}^{2} + 8x + 16y + 64 = 0$

Step-by-step explanation:

Just interchange the sign of y in the above equation given in the question.

Reason for doing so:

Since y axis changes signs about x-axis, hence in the equation just change (+)ve y by(-)ve y.

I hope I am able to clear your doubt.

Pls mark as brainliest answer!!