Find the equation of the contains the point (1,2),(1,-2)
Answers
Answer:
x = 1 is the equation of the line containing the points (1,2) and (1,-2)
Solution:
Given that,
We have to find the equation of the line containing the points (1,2) and (1,-2)
Find the slope of line
m = \frac{y_2-y_1}{x_2-x_1}m=
x
2
−x
1
y
2
−y
1
From given,
\begin{gathered}(x_1, y_1) = (1 , 2)\\\\(x_2, y_2) = (1 , - 2)\end{gathered}
(x
1
,y
1
)=(1,2)
(x
2
,y
2
)=(1,−2)
Therefore,
\begin{gathered}slope = \frac{-2-2}{1-1}\\\\slope = \frac{-4}{0}\end{gathered}
slope=
1−1
−2−2
slope=
0
−4
Thus slope of line is undefined
Therefore, line is parallel to y axis., which means vertical line
The equation of line parallel to y axis is given as: x = k
Where,
k is the x co-ordinate of line
From given, x = 1
Therefore,
The equation of line is x = 1
Learn more about this topic
Find the equation of the line whose X-Intercept is 3 and which is perpendicular to line 3x - y + 23 = 0
https://brainly.in/question/12580943
Find the equation of the line passing through the origin and which bisects the portion of the line 3x + y = 6 intercepted between the coordinate axes.