Find the equation of the diameter of the circle given by x²+y²-12x+4y+6=0
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x^2+y^2-12x+4y+6=0
compare with standerd form of circle
x^2+y^2+2gx+2fx+c=0
Find g and f
as we know that
radius of circle =root of g^2+f^2-c
radius=root of 36+4-2
radius=root 34
diameter 2root 34
compare with standerd form of circle
x^2+y^2+2gx+2fx+c=0
Find g and f
as we know that
radius of circle =root of g^2+f^2-c
radius=root of 36+4-2
radius=root 34
diameter 2root 34
kaushikravikant:
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where is the equation??
We have calculate the g and f,-ve of g and f are cente of circle. by hit and trial method we find a point which satisfy this equation that point is (1,1)
We have two point which lie on diameter, then we can find out its equation easily
point A (6,-2) as centre of circle. slope of line -3/5 and the pointof passing line is (1,1). equation of diameter is (y2-y1)= m (x2-x1). equation is 3x+5y-8
I didnot read your question carefully,plz mark as best for answer
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