Question

Find the equation of the ellipse in which length of minor axis is equal to the distance between foci, whose length of the latus rectum is 10 units and major axis is along x axis.

Answer 1

Answer:

I don't understand your question dude ☺️☺️

Answer 2

Answer:

Assuming that this was intended to be:

$9x2+16y2−144=0</p><p>$

$\frac{9x {}^{} }{144 \: x {}^{2} } \frac{16}{144 \: y {}^{2} } = 1$

$a=4 \\ b=3</p><p></p><p></p><p>$

$c = \sqrt{a {}^{2} - b {}^{2} } = \sqrt{7}$

$Foci: (− \sqrt{7 \: 0}$

$Major Axis: (−4,0)(−4,0), (4,0)$

$Minor Axis: (−3,0)(−3,0), (3,0)$

$Latus Rectum: (\sqrt{7} - \frac{9}{4} ) \: ( \sqrt{7 \: \frac{9}{4} }$

$with \: length 2 \frac{b {}^{2} }{a \: } = \frac{9}{2}$

$Eccentricity: e= \frac{c}{a} = \frac{ \sqrt{7} }{4} ≈0.661438</p><p>$