Question

Find the equation of the line : containing the point a(4, 3) and having inclination 120 o.

Answer 1

Answer:

general equation of straight line

(y-y1) =m(x-x1)

here y1=3 , x1=4, m=tan120= (-1/√3)

put all the values and get the result

Answer 2

Line would be $y-3 = -\sqrt{3}(x-4)$

Step-by-step explanation:

Since, the slope of a line is,

$m=\tan \theta$

Where,

$\theta$ = angle made by line with respect to x-axis or the inclination of line.

If $\theta = 120^{\circ}$

Slope of the line,

$m=\tan (120^{\circ})=\tan (90+30)^{\circ}=-\cot 30^{\circ}=-\sqrt{3}$

Now, equation of line passes through $(x_1, y_1)$ with slope m,

$y-y_1=m(x-x_1)$

Thus, the equation of line passes through (4, 3) with slope -√3,

$y-3 = -\sqrt{3}(x-4)$

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