Question

find the equation of the line containing the points (1,2) and (1,-2)​

Answer 1

Answer:

m = -2+2/ 1-1 = infinity

therefore, the line is parallel to y-axis

and passes through (1,0)

equation of the given line is

x=1 (ans)

Answer 2

x = 1 is the equation of the line containing the points (1,2) and (1,-2)​

Solution:

Given that,

We have to find the equation of the line containing the points (1,2) and (1,-2)​

Find the slope of line

$m = \frac{y_2-y_1}{x_2-x_1}$

From given,

$(x_1, y_1) = (1 , 2)\\\\(x_2, y_2) = (1 , - 2)$

Therefore,

$slope = \frac{-2-2}{1-1}\\\\slope = \frac{-4}{0}$

Thus slope of line is undefined

Therefore, line is parallel to y axis., which means vertical line

The equation of line parallel to y axis is given as: x = k

Where,

k is the x co-ordinate of line

From given, x = 1

Therefore,

The equation of line is x = 1

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