Question

Find the equation of the line cutting off ab intercept 3 from the axis of y and inclined at 30° to the axis of x

Answer 1

Answer:

x-y√3 + 3√3 = 0

Step-by-step explanation:

y = mx + c

(m = slope = tan(tetha) = tan 30° = 1/√3 )

( c= intercept 3 from the axis of y )

so equation will be =>

y = x/√3 + 3

√3y = x + 3√3

x-y√3 + 3√3 = 0