Question

Find the equation of the line interesting x axis at the distance of 3units to the point of origin with slope (-2)




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Answer 1

Given,

Let the line intersecting x - axis have m as it's slope

• $\sf{m = -2}$

Since,the line intersects x - axis at 3 units from the origin

• y coordinate would be 0
• x coordinate would be 3

The ordered pair would be (3,0) = (a,b)

Point Slope Form

$\boxed{ \sf{y - b = m(x - a)}}$

To finD

Equation of Line

Putting the values,we get :

$\tt{y - 0 = - 2(x - 3)} \\ \\ \leadsto \: \tt{y = - 2x + 6} \\ \\ \large{ \leadsto \boxed{ \boxed{\tt{2x + y - 6 = 0}}}}$

Equation of the line would be 2x + y = 6

Answer 2

Let the line intersecting x - axis have m as it's slope

\sf{m = -2}m=−2

Since,the line intersects x - axis at 3 units from the origin

y coordinate would be 0

x coordinate would be 3

The ordered pair would be (3,0) = (a,b)

Point Slope Form

\boxed{ \sf{y - b = m(x - a)}}

y−b=m(x−a)

To finD

Equation of Line

Putting the values,we get :

\begin{lgathered}\tt{y - 0 = - 2(x - 3)} \\ \\ \leadsto \: \tt{y = - 2x + 6} \\ \\ \large{ \leadsto \boxed{ \boxed{\tt{2x + y - 6 = 0}}}}\end{lgathered}

y−0=−2(x−3)

⇝y=−2x+6

⇝

2x+y−6=0

Equation of the line would be 2x + y = 6