Question

Find the equation of the line joining the origin to the point of intersection of x^2+y^2=1 and x+y=1​

Answer 1

Answer:

Step-by-step explanation:

Make x as the subject of the formula x+y=1

X=1-y

Then substitute 1-y in the place of x in x^2+y^2=1 so (1-y)^2-y^2=1

1-2y+y^2-y^2=1

Then y^2-y^2 cancelled to get 0

So 1-2y+y^2-y^2=1

1-2y=1

Collecting like terms together

-2y=1-1

-2y=0

-2y/-2=0/-2

y=0

Then substitute y by its value in x+y=1

x+0=1

x=1

Solution set, S={(1,0)}

Thanks for following.

Answer 2

Answer:

X=0 and Y=0

Step-by-step explanation:

X^2+Y^2=1 and X+Y=1

EQUATION OF PAIR OF STRAIGHT LINES FORMED BY JOINING ORIJIN AND P.O.I IS GIVEN BY

X^2+Y^2=(X+Y)^2

XY=0

X=0 ANDY=0

THIS METHOD IS CALLED ""HOMOGENIZATION ""

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