find the equation of the line joining the points (-7,6,13) and (7,-6,3)
neerjabinu:
if the former is correct then i can provide u the answer
-7,6,-3 & 7,-6,3
okay thanx
the one i pasted now is the point
r u in ignou
sorry im not getting the correct answer
ohh its ok
i got it right
and also has posted it
wheres it
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we know that the equations of the straight lines passing through the points (x1, y1, z1) and (x2, y2, z2) is
x-x1/x2-x1 = y-y1/y2-y1 = z-z1/z2-z1
now , the equation of straight lines joining the points (-7,6,-3) & (7,-6,3) is
x+7/14 = y-6/-12 = z+3/6
so , x+7/7 = y-6/-6 = z+3/3
x-x1/x2-x1 = y-y1/y2-y1 = z-z1/z2-z1
now , the equation of straight lines joining the points (-7,6,-3) & (7,-6,3) is
x+7/14 = y-6/-12 = z+3/6
so , x+7/7 = y-6/-6 = z+3/3
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