Question

Find the equation of the line making an angle of 150 with the x axis and passes through the point (3, -5)

Answer 1

slope of the line(m) = tan(150) =
$tan \: 150 = \frac{ - 1}{ \sqrt{3} }$
using one point and slope form
$(y - y1) = m(x - x1)$
where y1 = -5 And x1=3
$(y - ( - 5)) = \frac{ - 1}{ \sqrt{3} } \times (x - 3) \\ (y + 5) = \frac{ - 1}{ \sqrt{3} } \times (x - 3)$

The equation is
$\sqrt{3} y + x + 5 \sqrt{3} - 3 = 0$