Question

Find the equation of the line on which the perpendicular from the origin makes an angle of 30° with the X-axis and which forms a triangle of area
$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \ \frac{50}{ \sqrt{3} }$
square units with the axes.
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Answer 1

Answer:

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SoLuTioN

"Let the length of the perpendicular be p from the origin,

Hence, angle at origin will be 30 degree = alpha

X cos alpha + y sin alpha = p

X cos 30 + y sin 30 = p

x/2 + y square root 3/2 = p

x + y square root 3 = 2p    eq(1)

now in the triangle that will be made with x axis,

cos 30 = 2p/ square root 3

now in the triangle that will be with y axis,

cos 60 = 2p

Hence, area = 50/ square root 3

½ * 2p/square root 3 * 2p = 50/ square root 3

P^2 = 25

P = +_ 5

Hence, equation will be square root of (3x) + y = +_ 10

"

Answer 2

Step-by-step explanation:

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