Find the equation of the line parallel to 4x + 3y = 5 and having x-intercept (-3)
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Answered by
11
A line is parallel to given line only when
slope of both lines are equal .
Let slope of unknown line is P
slope of 4x + 3y = 5 is -4/3
hence, P = -4/3
A/C to question ,
unknown line passes through (-3, 0)
so, equation of line :
(y - 0) = -4/3(x +3)
y = -4/3(x + 3)
3y + 4(x + 3) = 0
4x + 3y + 12 = 0
hence, 4x + 3y = -12
slope of both lines are equal .
Let slope of unknown line is P
slope of 4x + 3y = 5 is -4/3
hence, P = -4/3
A/C to question ,
unknown line passes through (-3, 0)
so, equation of line :
(y - 0) = -4/3(x +3)
y = -4/3(x + 3)
3y + 4(x + 3) = 0
4x + 3y + 12 = 0
hence, 4x + 3y = -12
Answered by
1
Let slope of unknown line is P
slope of 4x + 3y = 5 is -4/3
hence, P = -4/3
A/C to question ,
unknown line passes through (-3, 0)
so, equation of line :
(y - 0) = -4/3(x +3)
y = -4/3(x + 3)
3y + 4(x + 3) = 0
4x + 3y + 12 = 0
hence, 4x + 3y = -12
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