find the equation of the line parallel to 6x-5y=10 that passes through the point (3,5)
Answers
Answer:
Example 4: Find the equation of a line passing through the point (3, –4) perpendicular to the line
8x + 6y = 15.
Step 1: Find the slope of the line.
To find the slope of the given line we need to get the line into slope-intercept form (y =
mx + b), which means we need to solve for y:
The slope of the line 8x + 6y = 15 is m = –4/3. Therefore, the slope of the line
perpendicular to this line would have to be m = 3/4.
Step 2: Use the slope to find the y-intercept.
Now that we know the slope of the line is 3/4 we can plug the slope into the equation and
we get:
Next use the given point to plug in for the values of x and y.
( ) (
) ( ) Multiply to simplify the problem.
(
)
Multiply the entire problem by 4 (the
common denominator) and the fractions will
go away.
–16 = 9 + 4b Solve for b and you will have the y-intercept.
Step 3: Write the answer.
Using the slope of 3/4 and the y-intercept of –25/4, the answer is:
