Question

Find the equation of the line parallel to line 3x+2y=8 and passing through the point (0,1).

Answer 1

$3x + 2y - 8 = 0 \\ slope = - \frac{a}{b} = - \frac{3}{2 } \\ m = - \frac{3}{2} \\ \\ y - y1 = m(x - x1) \\ y - 0 = - \frac{3}{2} (x - 1) \\ y = - \frac{3}{2}(x - 1) \\ 2y = - 3x - 3 \\ 3x + 2y + 3 = 0$

Answer 2

3x + 2y = 8

2y = −3x + 8

or, y = -3x/2 + 8/2

Slope of given line = -3/2

Since the required line is parallel to given straight line.

∴ Slope of required line (m) = -3/2  

Now the equation of the required line is given by: