Question

Find the equation of the line parallel to the line y = 4x – 2 that passes through the point (–1, 5). The slope of y = 4x – 2 is . The slope of a line parallel to y = 4x – 2 is . The equation of the line parallel to y = 4x – 2 that passes through the point (–1, 5) is y =

Answer 1

This is the required solution.

Hope this helps you.

Answer 2

Given:

y = 4x -2 passes through point (-1,5)

To find:

Equation of line parallel y = 4x -2 passes through point (-1,5)

The slope of a line parallel to y = 4x – 2

Solution:

Let (-1,5) be (x1,y1).

y = mx + c  (where m is the slope)

y = 4x -2

m = 4

Equation of line passing through point: y - y1 = m(x-x1)

y - 5 = 4(x - (-1))

y - 5 = 4x + 4

y = 4x + 9

Hence, Equation of line parallel y = 4x -2 passes through point (-1,5) is

y = 4x + 9.

The slope of a line parallel to y = 4x – 2  is 4.