Find the equation of the line pass through the given points (2,1/3) (-1/2, -2)
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Answer:
14x-15y-23=0
Step-by-step explanation:
Slope Point Form:y-y1=m(x-x1)
m=(y2-y1)/(x2-x1)
=((1/3)-(-2))/(2-(-1/2))
=(7/3)/(5/2)
=14/15
Now
y-y1=14/15(x-x1)
15(y-1/3)=14(x-2)
15y-5=14x-28
14x-15y-23=0
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