Math, asked by bkalyani1707, 2 months ago


Find the equation of the line passing through (-3, 5) and perpendicular
to the line through the points (2,5) and (-3,6).​

Answers

Answered by amritaprasad8b
1

Answer:The slope of line joining points (2,5) and (3,6) is m=  

−3−2

6−5

​  

=  

−5

1

​  

 

We know that, the two non-vertical lines are perpendicular to each other only if and only if their slopes are negative reciprocals of each other.

Therefore, slope of line perpendicular to the line through the points (2,3) and (−3,6)

=−  

m

1

​  

=−  

{  

5

−1

​  

}

1

​  

=5

Now equation of the line passing through points (−3,5) whose slope is 5 is  (y−5)=5(x+3).

⇒y−5=5x+15

⇒5x−y+20=0

Step-by-step explanation:

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