find the equation of the line passing through (4,-1) and having slope -6
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(4,-1)=x1,y1
m(-6)
equation of the line in slope point form
y-y1=m(x-x1)
y-(-1)=-6(x-4)
y+1=-6x+24
6x+y+1-24=0
6x+y-23=0
the equation of the line is 6x+y-23=0
m(-6)
equation of the line in slope point form
y-y1=m(x-x1)
y-(-1)=-6(x-4)
y+1=-6x+24
6x+y+1-24=0
6x+y-23=0
the equation of the line is 6x+y-23=0
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