Find the equation of the line passing through (-43) with slop [1/2]
Answers
Answer:
We know that the equation of line passing through point (x0,y0) whose slope is m is
(y−y0)=m(x−x0)
Thus the equation of line passing through the point (−4,3) whose slope is 21 is,
(y−3)=21(x+4)
⇒2(y−3)=(x+4)
⇒x−2y+10=0
EXPLANATION.
Equation of line.
Passing through the point = (-4,3).
Slope of the line = 1/2.
As we know that,
Formula of the equation of line.
⇒ (y - y₁) = m(x - x₁).
Put the values in the equation, we get.
⇒ (y - 3) = 1/2(x - (-4)).
⇒ (y - 3) = 1/2(x + 4).
⇒ 2(y - 3) = (x + 4).
⇒ 2y - 6 = x + 4.
⇒ x + 4 - 2y + 6 = 0.
⇒ x - 2y + 10 = 0.
MORE INFORMATION.
Different forms of the equation of straight line.
(1) = Slope = Intercept form : y = mx + c.
(2) = Slope point form : The equation of a line with slope m and passing through a point (x₁, y₁) is (y - y₁) = m(x - x₁).
(3) = Two point form : (y - y₁) = (y₂ - y₁)/(x₂ - x₁) (x - x₁).
(4) = Intercept form : x/a + y/b = 1.
(5) = Normal (perpendicular) form of a line : x cosα + y sinβ = p.
(6) = Parametric form (distance form) : (x - x₁)/cosθ = (y - y₁)/sinθ = r.