Question

find the equation of the line passing through -6, 1 and perpendicular to thr line through the points 2,5 and -4, 0​

Answer 1

Answer:

-10 3

Step-by-step explanation:

Answer 2

Answer:

y=(-6/5)x-31/5

Step-by-step explanation:

Call the line u need to find line 1 and the other line 2

First, u should find equation of line 2 in this form: y=ax+b

a2=(5-0)/(2+4) =5/6

Line 2 passes point (-4,0)

-> 0=(5/6)(-4)+b

-> so b2=10/3

So equation of line 2: y=(5/6)x+10/3

Line 1 is perpendicular to line 2  

=> a1 x a2 = -1

 a1 x (5/6) = -1

=> a1= -6/5

Line 1 passes point (-6,1)

=> 1=(-6/5)(-6)+b

b=-31/5

SO THE EQUATION OF LINE 1 IS y=(-6/5)x-31/5

(the below pic proves that Im correct)