Find the equation of the line passing through intersection of 2x+3y=1 and 3x+4y-6=0 and parallel to the line 5x-y=0?
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Step-by-step explanation:
2x+3y=1-----i)
3x+4y=6-----ii)
on solving both eq.
x=14,y=-9
points of intersection=(14,-9)
5x-y=0
y=5x
y=mx+c
m=5
slope of another line m1=5
eq. of line will be:
(y+9)=5(x-14)
y+9=5x-70
5x-y-79=0
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