Question

Find the equation of the line passing through intersection of 2x+3y=1 and 3x+4y-6=0 and parallel to the line 5x-y=0?

Answer 1

Step-by-step explanation:

2x+3y=1-----i)

3x+4y=6-----ii)

on solving both eq.

x=14,y=-9

points of intersection=(14,-9)

5x-y=0

y=5x

y=mx+c

m=5

slope of another line m1=5

eq. of line will be:

(y+9)=5(x-14)

y+9=5x-70

5x-y-79=0