Question

find the equation of the line passing through P (2,-4) and B (5,-2)

ch- eq.of straight line...
please please please please please answer me.....​

Answer 1

Answer:

2x-3y-16=0

Step-by-step explanation:

given,

p(2,-4) ; B(5,-2)- ( x1=2; x2=5; y1=-4; y2=-2)

then to use the formula: y-y1=m(x-x1) we need to find m(slope)

m=y2-y1/x2-x1

then on substituting we get:

m= -2-(-4)/5-2

=2/3  (slope)

Substituting m value in this equation-- y-y1=m(x-x1) [this formula is used to find the equation]

 y-y1=m(x-x1)

=y-(-4)=2/3(x-2)

=3(y+4)=2x-4.

=3y+12+4=2x

=3y-2x+16=0

= -(2x-3y-16)=0 [taking minus(-) common]

Answer=2x-3y-16=0

Please let me know whether this answer is right then it would be helpful:)