Question

find the equation of the line passing through point (-4,-3) and perpendicular to the straight line joining (1,3) and (2,7)

Answer 1

Slope of the line joining the points(1,3) and (2,7) is:
= 7-3/2-1
=4/1
=4
Therefore, equation of the line passing through the points(-4,-3) and having a slope of 4 is given by
y-(-3)=4*(x-(-4))
y+3=4*(x+4)
y+3=4x+16
4x-y+16-3=0
4x-y+13=0