Question

Find the equation of the line passing through the inters
son of the line passing through the intersection of the lines 4x + 3y = 1 and 5x + 4y = 2
and perpendicular to x-axis.​

Answer 1

Hence the eq. of required line is

x + 2 = 0

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Answer 2

Question :--- Find the equation of the line passing through the intersection of the lines 4x + 3y = 1 and 5x + 4y = 2

and perpendicular to x-axis.

Solution :----

→ 4x + 3y = 1 ------------------ Equation (1)

→ 5x + 4y = 2 ----------------- Equation (2)

Lets try to solve both first ,,

Multiply Equation (1) by 5 and Equation (2) by 4 and than subtracting both we get,,

→ 5(4x+3y) - 4(5x+4y) = 5*1 - 4*2

→ 20x + 15y - 20x -16y = 5 - 8

→ -y = -3

→ y = 3

Putting this in any Equation now we get,

→ 4x + 3*3 = 1

→ 4x = 1-9

→ 4x = (-8)

→ x = (-2) ..

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Now, when line is perpendicular to x - axis it remains constant ..[ x = c ]

so,

→ line perpendicular to x - axis = x = (-2)

or, x + 2 = 0 (Ans)