Question

find the equation of the line passing through the point (0, 3) and perpendicular to the line x-2y+5=0?​

Answer 1

Answer:

x+2y+3=0

Step-by-step explanation:

Given line is y=12x+52.Its slope is 12

m×12=−1⇒m=−2

Let y=-2x+c be the straight line.

Sicne, it passes through (0,3), we have 3=(−2)×0+c⇒c=3

∴m=−2andc=3.

Answer 2

Answer:

x-2y+5=0

2y=x+5

y=1/2x+5/2

Thus comparing with y=mx+c we got m=m1=1/2

Now as it is perpendicular so 1/2×m2=-1.Thus m2= -2

Thus,the equation of the line is

(y-3) = -2 (x-0)