Find the equation of the line passing through the point (1, 1) and the
perpendicular from the origin makes an angle 60 degree with x – axis.
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A horizontal line that runs through, say, (4,1) would have an equation of y = 1 and be parallel to the x-axis. A line perpendicular to the x-axis would have the opposite. The y-axis, for example, has an equation of x = 0 because any point on the y-axis has a y-value of 0.
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Step-by-step explanation:
As we know that,
cos2a+cos2b+cos2c=1
Here,
cosa=cos60°=21
cosb=3x
cosc=x
Here, x is constant,
Now,
41+3x2+x2=1
⇒4x2=1−41
⇒x=±43
Now, direction cosines of line L1-
21,43,43
direction cosines of line L1-
21,−43,−43
Angle between the lines, cosθ=41−169−163=−21
⇒θ=60°
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