Question

find the equation of the line passing through the point (-2,3) and having inclination 135°
​

Answer 1

Step-by-step explanation:

$\theta \: = 135 \degree \\ tan\theta = tan 135 \degree \\ tan\theta = - 1$

slope of line is -1

equation of line is

$(y - 3) = - 1(x + 2) \\ y - 3 = - x - 2 \\ x + y - 1 = 0$

Answer 2

Required Solution :-

Here we're given with a point that is (-2 , 3) from which a line is passing making an angle of 135° to the axis.

So simply we would be using the point-slope form of line :

• y - y₁ = m (x - x₁)

We have :

• y₁ = 3
• x₁ = -2

So we need to find out the slope (m) .

As we know that,

• m = tantheta
• m = tan 135°
• m = -1

Equation of line :

• y - 3 = -1 [x - (-2)]
• y - 3 = -1 (x + 2)
• y - 3 = -x - 2
• y + x = 3 - 2
• y + x = 1
• y + x - 1 = 0

Therefore :

• Equation of line is y + x - 1 = 0