Question

Find the equation of the line passing through the point (-3, 4) and perpendicular to the line 2x + 6y = 1​

Answer 1

Answer:

Given :-

point (-3, 4) and perpendicular to the line 2x + 6y = 1

To Find :-

Equation

Solution :-

We know that

Slope of line = b/a

Here,

b = 6

a = 2

Slope = 6/2

Slope = 3

Now,

Equation of line,

(y - y₁) = m(x - x₁).

Putting value

[y -(4)] = 3[x - (-3)].

y - 4 = 3(x + 3).

y - 4 = 3x + 9.

y - 3x = 9 + 4

y - 3x = 13.

Answer 2

y - 3x = 13

is your answer mate.