Question

Find the equation of the line passing through the point (_3,5) and perpendicular to the line through the points (2,5) and (_3,6)

Answer 1

Answer:

Step-by-step explanation:

first lets find the equation passing through points  (2,5) and (-3,6)

y-2=-1(x-5)

y-2=5-x

x+y=7

the point which is perpendicular to equation x+y=7 has equation

x-y=lamda

point which is perpendicular to equation x+y=7 will satisfy equation  x-y=lamda

putting 3 and 5 in above

-2=lamda

so equation is x-y=-2